cos(4x)=1-8sin^2(x)+8sin^4(x)

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Solution for cos(4x)=1-8sin^2(x)+8sin^4(x) equation: 


Simplifying
cos(4x) = 1 + -8sin2(x) + 8sin4(x)

Remove parenthesis around (4x)
cos * 4x = 1 + -8sin2(x) + 8sin4(x)

Reorder the terms for easier multiplication:
4cos * x = 1 + -8sin2(x) + 8sin4(x)

Multiply cos * x
4cosx = 1 + -8sin2(x) + 8sin4(x)

Multiply in2s * x
4cosx = 1 + -8in2sx + 8sin4(x)

Multiply in4s * x
4cosx = 1 + -8in2sx + 8in4sx

Solving
4cosx = 1 + -8in2sx + 8in4sx

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '4osx'.
c = 0.25o-1s-1x-1 + -2in2o-1 + 2in4o-1

Simplifying
c = 0.25o-1s-1x-1 + -2in2o-1 + 2in4o-1

Reorder the terms:
c = -2in2o-1 + 2in4o-1 + 0.25o-1s-1x-1

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